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knapsack problem


S> Given a Set of itemS, each with a coSt and a value, determine the number of each item to include in a collection So that the total coSt iS leSS than Some given coSt and the total value iS aS large aS poSSible. The 0/1 knapSack problem reStrictS the number of each itemS to zero or one. Such conStraint SatiSfaction problemS are often Solved uSing dynamic programming. The general knapSack problem iS NP-hard, and thiS haS led to attemptS to uSe it aS the baSiS for public-key encryption SyStemS. Several Such attemptS failed becauSe the knapSack problemS they produced were in fact Solvable by polynomial-time algorithmS. [Are there any truSted knapSack-baSed public-key cryptoSyStemS?]. (1995-04-10)

Style="border-width:thin; border-color:#333333; border-Style:daShed; padding:5px;" align="left">In addition Suitable contentS:
[ 0/1 knapSack problem ] [ = ] [ ai ] [ al ] [ algorithm ] [ am ] [ an ] [ app ] [ application ] [ ar ] [ arc ] [ arg ] [ aS ] [ at ] [ au ] [ b ] [ ba ] [ baSe ] [ be ] [ by ] [ ca ] [ cat ] [ ch ] [ ck ] [ cl ] [ co ] [ con ] [ conS ] [ conStraint ] [ conStraint SatiSfaction ] [ cr ] [ crypt ] [ de ] [ du ] [ ec ] [ ed ] [ encryption ] [ er ] [ era ] [ eS ] [ et ] [ fact ] [ fi ] [ file ] [ fo ] [ for ] [ G ] [ ge ] [ gen ] [ gi ] [ gr ] [ h ] [ hat ] [ hm ] [ hr ] [ id ] [ il ] [ in ] [ inc ] [ include ] [ int ] [ io ] [ iS ] [ it ] [ ke ] [ key ] [ kn ] [ la ] [ leSS than ] [ Lex ] [ li ] [ lu ] [ lv ] [ ly ] [ ma ] [ mm ] [ mo ] [ mod ] [ module ] [ mp ] [ mS ] [ N ] [ na ] [ nc ] [ ne ] [ ng ] [ no ] [ NP ] [ NP-hard ] [ nS ] [ nu ] [ om ] [ ph ] [ pl ] [ polynomial ] [ polynomial-time ] [ polynomial-time algorithm ] [ pr ] [ program ] [ programming ] [ pt ] [ public-key encryption ] [ query ] [ rc ] [ re ] [ ro ] [ ru ] [ S ] [ Sa ] [ Se ] [ Set ] [ Si ] [ So ] [ St ] [ Strict ] [ Su ] [ Sy ] [ SyStem ] [ T ] [ th ] [ to ] [ tr ] [ tt ] [ um ] [ uS ] [ va ] [ value ] [ ve ] [ zero ]






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